LibraryApplications of Definite Integrals

Applications of Definite Integrals

Learn about Applications of Definite Integrals as part of JEE Mathematics Mastery - Calculus and Algebra

Applications of Definite Integrals in Competitive Exams

Definite integrals are powerful tools in mathematics, with numerous applications extending beyond finding areas under curves. In competitive exams like JEE, understanding these applications is crucial for solving complex problems efficiently. This module explores key areas where definite integrals are applied, equipping you with the knowledge to tackle these questions with confidence.

Area Between Curves

One of the most common applications of definite integrals is finding the area enclosed by two or more curves. This involves identifying the points of intersection of the curves and then integrating the difference between the upper and lower curves with respect to the appropriate variable (x or y) between these intersection points.

Integrate the difference between the 'upper' and 'lower' functions to find the area between them.

To find the area between two curves, y=f(x)y = f(x) and y=g(x)y = g(x), from x=ax=a to x=bx=b, where f(x)g(x)f(x) \ge g(x) for all xx in [a,b][a, b], we compute ab[f(x)g(x)]dx\int_{a}^{b} [f(x) - g(x)] dx. The limits of integration, aa and bb, are often the x-coordinates of the points where the curves intersect.

Consider two continuous functions, f(x)f(x) and g(x)g(x), such that f(x)g(x)f(x) \ge g(x) for all xx in the interval [a,b][a, b]. The area AA of the region bounded by the graphs of y=f(x)y = f(x), y=g(x)y = g(x), and the vertical lines x=ax = a and x=bx = b is given by the definite integral: A=ab[f(x)g(x)]dxA = \int_{a}^{b} [f(x) - g(x)] dx If the curves intersect, the limits of integration aa and bb are typically the x-coordinates of these intersection points. If the region is bounded by curves x=p(y)x = p(y) and x=q(y)x = q(y) from y=cy = c to y=dy = d, where p(y)q(y)p(y) \ge q(y), the area is given by: A=cd[p(y)q(y)]dyA = \int_{c}^{d} [p(y) - q(y)] dy

What is the primary operation used to calculate the area between two curves?

Integrating the difference between the upper and lower curves.

Volume of Solids of Revolution

When a region in the plane is revolved around an axis (either the x-axis, y-axis, or another line), it forms a solid of revolution. Definite integrals can be used to calculate the volume of these solids using methods like the Disk Method, Washer Method, and Shell Method.

Summing up infinitesimally thin slices (disks, washers, or shells) to find the total volume.

The Disk Method calculates the volume of a solid formed by revolving a region bounded by y=f(x)y=f(x), the x-axis, and x=a,x=bx=a, x=b around the x-axis as V=πab[f(x)]2dxV = \pi \int_{a}^{b} [f(x)]^2 dx. The Washer Method is used when there's a gap between the region and the axis of revolution.

  1. Disk Method: If a region bounded by y=f(x)y = f(x), the x-axis, x=ax = a, and x=bx = b is revolved around the x-axis, the volume VV is given by: V=πab[f(x)]2dxV = \pi \int_{a}^{b} [f(x)]^2 dx If revolved around the y-axis, and the region is bounded by x=g(y)x = g(y), the y-axis, y=cy = c, and y=dy = d, the volume is: V=πcd[g(y)]2dyV = \pi \int_{c}^{d} [g(y)]^2 dy 2. Washer Method: If a region between y=f(x)y = f(x) (outer radius) and y=g(x)y = g(x) (inner radius) is revolved around the x-axis from x=ax = a to x=bx = b, the volume is: V=πab[[f(x)]2[g(x)]2]dxV = \pi \int_{a}^{b} [[f(x)]^2 - [g(x)]^2] dx 3. Shell Method: If a region bounded by y=f(x)y = f(x), the x-axis, x=ax = a, and x=bx = b is revolved around the y-axis, the volume is: V=2πabxf(x)dxV = 2\pi \int_{a}^{b} x f(x) dx

Visualizing the Disk Method: Imagine slicing the solid of revolution into infinitesimally thin disks. The radius of each disk is the function value f(x)f(x) at a given xx, and the thickness is dxdx. The volume of a single disk is approximately π[f(x)]2dx\pi [f(x)]^2 dx. Summing these volumes from aa to bb using integration gives the total volume.

📚

Text-based content

Library pages focus on text content

What is the formula for the volume of a solid of revolution using the Disk Method when revolving around the x-axis?

V=πab[f(x)]2dxV = \pi \int_{a}^{b} [f(x)]^2 dx

Arc Length

The definite integral can also be used to calculate the length of a curve between two points. This involves integrating the square root of 1 plus the square of the derivative of the function.

Summing infinitesimal straight line segments along the curve.

The arc length LL of a curve y=f(x)y = f(x) from x=ax = a to x=bx = b is given by L=ab1+[f(x)]2dxL = \int_{a}^{b} \sqrt{1 + [f'(x)]^2} dx.

The arc length LL of a curve defined by y=f(x)y = f(x) from x=ax = a to x=bx = b is given by the integral: L=ab1+(dydx)2dxL = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} dx If the curve is defined parametrically by x=x(t)x = x(t) and y=y(t)y = y(t) for t1tt2t_1 \le t \le t_2, the arc length is: L=t1t2(dxdt)2+(dydt)2dtL = \int_{t_1}^{t_2} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} dt

What is the integrand for calculating the arc length of a curve y=f(x)y=f(x)?

1+[f(x)]2\sqrt{1 + [f'(x)]^2}

Work Done by a Variable Force

In physics, the work done by a force is often calculated by integrating the force function over the distance over which it acts. This is particularly useful when the force is not constant.

Work is the integral of force with respect to displacement.

If a force F(x)F(x) acts on an object along the x-axis from position x=ax=a to x=bx=b, the work done WW is W=abF(x)dxW = \int_{a}^{b} F(x) dx.

When a force F(x)F(x) varies with position xx, the work WW done by this force in moving an object from position aa to position bb along a straight line is given by the definite integral: W=abF(x)dxW = \int_{a}^{b} F(x) dx This concept is fundamental in physics, for example, in calculating the work done to stretch or compress a spring (Hooke's Law, F=kxF = -kx).

What physical quantity is calculated by integrating a variable force over a distance?

Work done.

Average Value of a Function

The average value of a function over an interval represents the height of a rectangle that has the same area as the region under the curve of the function over that interval.

The average value is the total 'value' divided by the 'extent'.

The average value of a function f(x)f(x) over the interval [a,b][a, b] is given by favg=1baabf(x)dxf_{avg} = \frac{1}{b-a} \int_{a}^{b} f(x) dx.

The average value of a continuous function f(x)f(x) over the interval [a,b][a, b] is defined as: favg=1baabf(x)dxf_{avg} = \frac{1}{b-a} \int_{a}^{b} f(x) dx This formula essentially divides the total 'area' under the curve by the 'width' of the interval to find an equivalent constant height.

How do you calculate the average value of a function f(x)f(x) over [a,b][a, b]?

1baabf(x)dx\frac{1}{b-a} \int_{a}^{b} f(x) dx

Practice and Strategy

Mastering these applications requires consistent practice. Focus on understanding the underlying geometric or physical interpretation of each problem. When solving, always identify the correct limits of integration and the function to be integrated. Sketching the curves or visualizing the solid can be immensely helpful.

For competitive exams, recognizing the problem type (area, volume, arc length, work, average value) is the first crucial step. Then, correctly setting up the definite integral is key to arriving at the solution.

Learning Resources

Applications of Definite Integrals - Khan Academy(documentation)

Provides comprehensive video lessons and practice exercises on various applications of definite integrals, including area between curves and volumes of revolution.

JEE Mathematics: Applications of Definite Integrals - Byju's(blog)

A detailed explanation of applications of definite integrals with examples tailored for JEE preparation, covering area, volume, and arc length.

Volumes of Solids of Revolution - Paul's Online Math Notes(documentation)

In-depth notes on calculating volumes of solids of revolution using the disk and washer methods, with clear examples.

Arc Length of a Curve - Brilliant.org(documentation)

Explains the concept of arc length and how to calculate it using definite integrals, with interactive examples.

Work Done by a Variable Force - Physics Classroom(documentation)

A clear explanation of how to calculate work done by a variable force using integration, with real-world physics examples.

Average Value of a Function - Mathematics LibreTexts(documentation)

Defines and illustrates the concept of the average value of a function over an interval, including its formula and applications.

JEE Advanced Maths - Applications of Integration - YouTube Playlist(video)

A curated playlist of YouTube videos covering various applications of definite integrals relevant to JEE Advanced mathematics.

Area Between Curves - Practice Problems - Art of Problem Solving(documentation)

Provides a collection of practice problems and explanations for finding the area between curves, often with a competitive exam focus.

Calculus Applications: Solids of Revolution - MIT OpenCourseware(documentation)

Problem sets and solutions from MIT's single-variable calculus course, focusing on applications of integration including solids of revolution.

Integral Calculus Applications - NPTEL(video)

Video lectures from NPTEL covering various aspects of integral calculus, including detailed discussions on applications relevant to engineering and competitive exams.