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Section Formula

Learn about Section Formula as part of JEE Mathematics Mastery - Calculus and Algebra

Mastering the Section Formula in Coordinate Geometry

Welcome to this module on the Section Formula, a fundamental concept in coordinate geometry. Understanding how to find the coordinates of a point that divides a line segment in a given ratio is crucial for solving a wide range of problems in competitive exams like JEE. This formula allows us to break down complex geometric relationships into algebraic equations.

Understanding the Section Formula

The Section Formula helps us determine the coordinates of a point that divides the line segment joining two given points, say P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2), internally in a specific ratio m:nm:n. This means the point lies between P and Q.

The Section Formula finds a point dividing a line segment internally.

If a point R(x,y)R(x, y) divides the line segment joining P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2) internally in the ratio m:nm:n, its coordinates are given by: x=mx2+nx1m+nx = \frac{mx_2 + nx_1}{m+n} and y=my2+ny1m+ny = \frac{my_2 + ny_1}{m+n}.

Let the two points be P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2). Let R(x,y)R(x, y) be a point that divides the line segment PQ internally in the ratio m:nm:n. This means that the distance PR is mm parts and the distance RQ is nn parts. Using similar triangles and coordinate geometry principles, we can derive the coordinates of R. The x-coordinate of R is found by taking a weighted average of the x-coordinates of P and Q, where the weights are the ratio mm and nn. Similarly, the y-coordinate of R is found by taking a weighted average of the y-coordinates of P and Q. The formula is: x=mx2+nx1m+nx = \frac{mx_2 + nx_1}{m+n} and y=my2+ny1m+ny = \frac{my_2 + ny_1}{m+n}.

What are the coordinates of a point that divides the line segment joining (2, 3) and (6, 7) internally in the ratio 1:2?

Using the section formula: x=16+221+2=6+43=103x = \frac{1*6 + 2*2}{1+2} = \frac{6+4}{3} = \frac{10}{3} and y=17+231+2=7+63=133y = \frac{1*7 + 2*3}{1+2} = \frac{7+6}{3} = \frac{13}{3}. The coordinates are (103,133)(\frac{10}{3}, \frac{13}{3}).

Special Cases and Applications

The Section Formula has several important applications, including finding the midpoint of a line segment and understanding how points divide a line segment externally.

ScenarioFormula for x-coordinateFormula for y-coordinate
Internal Division (ratio m:n)mx2+nx1m+n\frac{mx_2 + nx_1}{m+n}my2+ny1m+n\frac{my_2 + ny_1}{m+n}
Midpoint Division (ratio 1:1)x1+x22\frac{x_1 + x_2}{2}y1+y22\frac{y_1 + y_2}{2}
External Division (ratio m:n)mx2nx1mn\frac{mx_2 - nx_1}{m-n}my2ny1mn\frac{my_2 - ny_1}{m-n}

Remember that for external division, the ratio m:nm:n is used, but the formula involves subtraction. Ensure mnm \neq n for external division.

The midpoint formula is a direct consequence of the section formula when the ratio is 1:1. This simplifies finding the center point of any line segment.

Visualizing the Section Formula: Imagine a line segment on a coordinate plane. The section formula essentially finds a point on this segment by 'weighting' the coordinates of the endpoints by the ratio of the segments they create. For internal division, the point lies between the two endpoints. For external division, the point lies on the line extending beyond one of the endpoints.

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Practice Problems and JEE Relevance

The Section Formula is a building block for many JEE problems. You'll encounter it in questions involving centroids of triangles, properties of quadrilaterals, and locus problems. Practicing diverse problems will solidify your understanding and speed.

What is the formula for the x-coordinate when a point divides a line segment externally in the ratio m:n?

x=mx2nx1mnx = \frac{mx_2 - nx_1}{m-n}

Learning Resources

Section Formula - Coordinate Geometry | Maths(documentation)

Provides a clear explanation and formula for the section formula, with examples.

Section Formula - Definition, Formula, Examples(blog)

Explains the section formula with detailed derivations and solved examples, including internal and external division.

Coordinate Geometry - Section Formula(documentation)

A comprehensive guide to the section formula, covering its derivation and applications.

Section Formula | Coordinate Geometry(blog)

Details the section formula for internal and external division, along with practice problems.

Coordinate Geometry: Section Formula(documentation)

Offers a concise explanation of the section formula and its use in finding coordinates.

Section Formula - Maths(documentation)

Explains the section formula with a focus on its application in coordinate geometry problems.

Coordinate Geometry - Section Formula(wikipedia)

While not solely on section formula, this page provides context for coordinate geometry and related concepts.

Section Formula - Coordinate Geometry(blog)

A blog post explaining the section formula and its importance in competitive exams.

Coordinate Geometry - Section Formula(tutorial)

A step-by-step tutorial with examples on how to use the section formula.

Section Formula - Coordinate Geometry(documentation)

Provides a detailed explanation of the section formula, including its derivation and application in JEE preparation.